Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesMedium2 min

MathematicsMediumsingle choice

The area bounded between the curves $y = 4 - x^{2}$ and $y^{2} = 3∣ x ∣$ is equal to:

Answer:

Solution:

The required area is given by:

$2 \int_{0}^{1} (4 - x^{2} - 3 x) d x$

This evaluates to:

$2 (\frac{x}{2} 4 - x^{2} + \frac{4}{2} sin^{- 1} (\frac{x}{2}) - \frac{3 \cdot 2 x ^{3/2}}{3})_{0}^{1}$

The final result is:

$\frac{2 π - 3}{3}$

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

⏱ 2m

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