Mathematics - Area Under Curves Question with Solution | TestHub

Required Area $={\int }_{y=0}^8{y}^{1/3}dy$
$$\begin{array}{rl}& ={\frac{y^{1/3+1}}{\frac{1}{3}+1}|}_0^8={\frac{3}{4}\left(y^{4/3}\right)|}_0^8\\ & =\frac{3}{4}\left[(8{)}^{4/3}-0\right]=\frac{3}{4}\left[2^4\right]\\ & =\frac{3}{4}\times 16=12\text{ sq. unit. }\end{array}$$