For L. P. P, maximize z = 4 x 1 + 2 x 2 subject to 3 x 1 + 2 x 2 ≥ 9 , x 1 - x 2 ≤ 3 , x 1 ≥ 0 , x 2 ≥ 0 has ….

We have, maximise z = 4 x 1 + 2 x 2 Subject to constracts, 3 x 1 + 2 x 2 ≥ 9 , x 1 - x 2 ≤ 3 , x 1 ≥ 0 , x 2 ≥ 0 On taking given constraints as equation, we get the following graphs Here, we get feasible region is unbounded.

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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesHard2 minPYQ_2019

MathematicsHardsingle choice

For L. P. P, maximize $z = 4 x_{1} + 2 x_{2}$ subject to $3 x_{1} + 2 x_{2} \geq 9, x_{1} - x_{2} \leq 3, x_{1} \geq 0, x_{2} \geq 0$ has ….

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We have, maximise $z = 4 x_{1} + 2 x_{2}$
Subject to constracts, $3 x_{1} + 2 x_{2} \geq 9, x_{1} - x_{2} \leq 3, x_{1} \geq 0, x_{2} \geq 0$
On taking given constraints as equation, we get the following graphs

Here, we get feasible region is unbounded.

Stream:MHT_CETSubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

⏱ 2mℹ️ Source: PYQ_2019

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