The area (in sq. units) of the region { ( x , y ) : 0 ≤ y ≤ 2∣ x ∣ + 1 , 0 ≤ y ≤ x 2 + 1 , ∣ x ∣ ≤ 3 } is

Area = 2 [ ∫ 0 2 ( x 2 + 1 ) d x + 2 1 [ 5 + 7 ] × 1 ] = 3 64

Mathematics - Area under the curve Question with Solution | TestHub

MathematicsArea under the curveArea under the curveMedium2 minPYQ_2025

MathematicsMediumsingle choice

The area (in sq. units) of the region
${(x, y) : 0 \leq y \leq 2∣ x ∣ + 1, 0 \leq y \leq x^{2} + 1, ∣ x ∣ \leq 3}$ is

Answer:

Solution:

$Area = 2 [\int_{0}^{2} (x^{2} + 1) d x + \frac{1}{2} [5 + 7] \times 1] = \frac{64}{3}$

Stream:JEESubject:MathematicsTopic:Area under the curveSubtopic:Area under the curve

⏱ 2mℹ️ Source: PYQ_2025

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