Mathematics - Area Under Curves Question with Solution | TestHub

The area of the region$OCD$is
$=\underset{0}{\overset{1}{\int }}\left[4-\left(x^2+3x\right)\right]dx={\left[4x-\frac{x^3}{3}-\frac{3x^2}{2}\right]}_0^1=4-\frac{1}{3}-\frac{3}{2}=\frac{13}{6}$
So, the area of the given region$OABC$is
$=$Area of$OABD$$-$Area of$OCD$
$=3\times 4-\frac{13}{6}$
$=\frac{59}{6}$