Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMaxima-MinimaMedium2 minQB

MathematicsMediumsingle choice

If $x^{2} + 9 y^{2} = 1$ , then minimum and maximum value of $3 x^{2} - 27 y^{2} + 24 x y$ is

Answer:

Solution:

Put $x = cos θ, y = \frac{1}{3} sin θ$

$Let u = 3 x^{2} - 27 y^{2} + 24 x y u = 3 cos 2 θ + 4 sin 2 θ - 5 \leq u \leq 5$

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima

⏱ 2mℹ️ Source: QB

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