Mathematics - Application of Derivative Question with Solution | TestHub

Length of sub normal $=\left|y_{1}m\right|$, Length of sub tangent $=\left|\frac{y_1}{m}\right|$ $p|ym|=q{\left|\frac{y}{m}\right|}^2\Rightarrow \frac{p}{q}=\left|\frac{y}{m^3}\right|$ Here $m=\frac{dy}{dx}=\frac{3(x+a{)}^2}{2y}\Rightarrow m^3=\frac{27(x+a{)}^6}{8y^3}=\frac{27(x+a{)}^{3/2}}{8}$ $\Rightarrow \frac{p}{q}=\frac{8}{27}$