Mathematics - Application of Derivative Question with Solution | TestHub

\begin{array}{|c|c|c|} \hlinex & 0 & 2 \\ \hliner(x) & 0 & 16 \\ \hline \end{array} Let $r(x)=f(x)\cdot g(x)$ $=x^2\cdot 2x=2x^3$ $r^{\prime }(x)=6x^2$ Put $6x^2=0,\therefore x=0$ $\mathrm{Max}r(x)=2(2{)}^3=16$ or Max $(f(x),g(x))=16$ $I(x)={\int }_0^{2}16dx$ $I(x)=[16x{]}_0^2=32-0=32$