The value of k such that 1 x − 4 = 1 y − 2 = 2 z − k lies in the plane 2 x − 4 y + z = 7 , is

∵ 2 × 1 − 4 × 1 + 1 × 2 = 0 i.e. line is parallel to the plane now 2 × 4 − 4 × 2 + K = 7 (for having a common point) ⇒ K = 7

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Mathematics - 3D-Coordinate Geometry Question with Solution | TestHub

Mathematics3D-Coordinate GeometryMiscellaneous/MixedEasy2 minPYQ_2022

MathematicsEasysingle choice

The value of $k$ such that $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$ lies in the plane $2 x - 4 y + z = 7$ , is

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Solution:

$∵ 2 \times 1 - 4 \times 1 + 1 \times 2 = 0$ i.e. line is parallel to the plane now $2 \times 4 - 4 \times 2 + K = 7$ (for having a common point) $\Rightarrow K = 7$

Stream:MHT_CETSubject:MathematicsTopic:3D-Coordinate GeometrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2022

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