Mathematics - 3D-Coordinate Geometry Question with Solution | TestHub

Let $A(\vec{a})$ and $B(\vec{b})$ be points on two skew lines $\vec{r}=\vec{a}+\lambda \vec{p}$ and $\vec{r}=\vec{b}+u\vec{q}$ and the shortest distance between the skew lines is 1, where $\vec{p}$ and $\vec{q}$ are unit vectors forming adjacent sides of a parallelogram enclosing an area of $\frac{1}{2}$ units. If the angle between AB and the line of shortest distance is $60^{\circ }$, then $\mathrm{AB}=$