Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Let the slope of required line by $\mathrm{m}$ then $\tan 45^{\circ }=\left|\frac{m-\frac{1}{2}}{1+m\times \frac{1}{2}}\right|$ $\begin{array}{rl}& \Rightarrow \pm 1=\frac{m-\frac{1}{2}}{1+m\times \frac{1}{2}}\\ & \Rightarrow m=3\text{ or }m=-\frac{1}{3}\end{array}$ So, required equation $\begin{array}{rl}& (y-2)=3(x-3)\text{ or }(y-2)=\frac{-1}{3}(x-3)\\ & \Rightarrow 3x-y-7=0\text{ or }x+3y-9=0\end{array}$