If the lines giviven by 2 λ x − 1 = − 5 y − 1 = 2 z − 1 and λ x + 2 = λ y + 3 = 1 z + 5 are parallel, then the value\epsilone

(A) Line 2 λ x − 1 = − 5 y − 1 = 2 z − 1 has direction ratios 2 λ , − 5 , 2 Line λ x + 2 = λ y + 3 , 1 z + 5 has direction ratios λ , λ , 1 Since lines are parallel, λ 2 λ = λ − 5 = 1 2 ⇒ λ = 2 − 5

Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryCoordinates of a point in space, Direction cosines,Easy2 minPYQ_2020

MathematicsEasysingle choice

If the lines giviven by $\frac{x - 1}{2 λ} = \frac{y - 1}{- 5} = \frac{z - 1}{2}$ and $\frac{x + 2}{λ} = \frac{y + 3}{λ} = \frac{z + 5}{1}$ are parallel, then the value\epsilone

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(A) Line $\frac{x - 1}{2 λ} = \frac{y - 1}{- 5} = \frac{z - 1}{2}$ has direction ratios $2 λ, - 5, 2$ Line $\frac{x + 2}{λ} = \frac{y + 3}{λ}, \frac{z + 5}{1}$ has direction ratios $λ, λ, 1$ Since lines are parallel, $\frac{2 λ}{λ} = \frac{- 5}{λ} = \frac{2}{1} \Rightarrow λ = \frac{- 5}{2}$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Coordinates of a point in space, Direction cosines,

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