Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minQB

PhysicsMediuminteger

Find longitudinal magnification of a image of length 1 mm put at a distance 30 cm in front of concave mirror of focal length 20 cm.

Answer:

Solution:

$\frac{1}{v} + \frac{1}{- 30} = \frac{1}{- 20} \Rightarrow v = - 60 cm$

Lateral magnification $m = - \frac{v}{u} = - 2$ .

Longitudinal magnification $m^{2} = 4$ (image length 4 mm).

Answer: 4

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: QB

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