Start Free Mock LoginAlready registered? Login here

Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceEasy2 minPYQ_2020

PhysicsEasysingle choice

A slab of a glass of refractive index $1.5$ and thickness $3 cm$ is placed with the faces perpendicular to the principal axes of a concave mirror. If the radius of curvature of the mirror is $10 cm$ , the distance at which an object must be placed from the mirror so that image coincides with the object is

Options:

Answer:

Solution:

$μ = 1.5 = 3 / 2$

$Δ x = t (1 - \frac{1}{μ}) = 3 [1 - \frac{1}{3 / 2}] = 3 (\frac{1}{3})$

$Δ x = 1 cm$

object distance = 10 + 1 = 11 cm

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...