Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB
ChemistryMediummultiple choice
The normal boiling point of a liquid is 350 K and Δ Hvap is 35 kJ/mol. Assume that Δ Hvap is independent from temperature and pressure. The correct statement(s) is/are
Options:(select one or more)
Answer:
A, B, D
Solution:
At 1 atm and 350 K: Δ S = 35000/350 = 100 J/K-mol and Δ G = 0. Vaporising to vapour at pressure P: Δ S = 100 - Rln P and Δ G = RTln P. At 0.5 atm Δ S = 100 + 5.76 > 100 and Δ G = RTln 0.5 < 0: (a), (b) true. At 2 atm Δ S = 100 - 5.76 < 100: (c) false; Δ G = RTln 2 > 0: (d) true. Ans: (a), (b), (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy
⏱ 2mℹ️ Source: QB
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