Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB
ChemistryMediummultiple choice
Select the correct statement(s)
Options:(select one or more)
Answer:
A, B, C
Solution:
(a) dG = -S dT + V dP for reversible change with only P-V work, so Δ G = 0 at constant T, P: true. (b) Reversible means Δ Ssys + Δ Ssurr = 0: true. (c) δ qrev = 0 gives dS = 0: true. (d) A closed system can absorb heat reversibly, with Δ Ssys = qrev/T ≠ 0 (e.g. reversible isothermal expansion): false. Ans: (a), (b), (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy
⏱ 2mℹ️ Source: QB
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