One mole of ice is converted into water at 273 K . The entropies of H 2 O ( s ) and H 2 O ( l ) are 38.20 and 60.01 J mole − 1 K − 1 respectively. The enthalpy change for the conversion is

Question

One mole of ice is converted into water at 273 K . The entropies of H 2 ​ O ( s ) and H 2 ​ O ( l ) are 38.20 and 60.01 J mole − 1 K − 1 respectively. The enthalpy change for the conversion is

TestHub · Accepted Answer

Δ G = Δ H − T Δ S . At equilibrium, Δ G = 0 , so Δ H = T Δ S . Δ H = 273 × ( 60.01 − 38.20 ) = 5954.13 J m o l − 1 .

Chemistry - Thermodynamics - II Question with Solution | TestHub

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