Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
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The efficiency of a Carnot cycle is 1/5. When the temperature of the sink is lowered by 60°C, the efficiency becomes 2/5. The temperature of the source is

Options:

Answer:
A
Solution:

Tc/Th = 4/5. After lowering: (Tc - 60)/Th = 3/5. Subtract: 60/Th = 1/5, so Th = 300 K = 27°C. Matches (a).

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
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