Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIGibb's Free EnergyEasy2 minQB
ChemistryEasymultiple choice
Any process will be spontaneous at constant pressure and temperature when
Options:(select one or more)
Answer:
B, C, D
Solution:
Spontaneity needs Δ Suniv = Δ Ssys + Δ Ssurr > 0. At constant T and P (only P-V work) this is the same as Δ Gsys < 0. A negative Δ H alone is not sufficient, since TΔ S may outweigh it. Ans: (b), (c), (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy
⏱ 2mℹ️ Source: QB
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