An ideal gas undergoes a cyclic process as shown in figure.
$Δ U_{BC} = - 5 kJmol^{- 1}$ ,
$q_{AB} = 2 kJmol^{- 1}$ ,
$W_{A B} = - 5 kJmol^{- 1}$ ,
$W_{CA} = 3 kJmol^{- 1}$
Heat absorbed by the system during process CA is:

Question

An ideal gas undergoes a cyclic process as shown in figure.

$Δ U_{BC} = - 5 kJmol^{- 1}$ ,

$q_{AB} = 2 kJmol^{- 1}$ ,

$W_{A B} = - 5 kJmol^{- 1}$ ,

$W_{CA} = 3 kJmol^{- 1}$

Heat absorbed by the system during process CA is:

TestHub · Accepted Answer

Δ U BC ​ = − 5 kJ / mol Δ U A B ​ = q A B ​ + W A B ​ = 2 + ( − 5 ) For cyclic process, Δ U = 0 ⇒ Δ U AB ​ = Δ U BC ​ + Δ U CA ​ = 0 ⇒ Δ U CA ​ = − ( − 3 ) − ( − 5 ) = 8 kJ / mol As, Δ U CA ​ = q CA ​ + W CA ​ ⇒ 8 = q C A ​ + 3 ⇒ q CA ​ = + 5 kJ / mol

Chemistry - Thermodynamics - II Question with Solution | TestHub

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