Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IIGibb's Free EnergyEasy2 minQB
ChemistryEasysingle choice
A definite mass of a monoatomic ideal gas at 1 bar and 27°C expands against vacuum from 1.0 dm³ to 2.0 dm³. The change in free energy of the gas, ΔG, is (R = 0.08 bar-L/K-mol, ln 2 = 0.7)
Options:
Answer:
A
Solution:
n = PV/RT = 1 × 1.0/(0.08 × 300) = 1/24 mol. Free expansion of an ideal gas is isothermal and G is a state function, so ΔG = nRT ln(V₁/V₂) = (1/24) × 0.08 × 300 × (−ln 2) = −0.7 bar-L = −70 J. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy
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