In a one-litre flask, 6 moles of A undergoes the reaction A ( g ) ⇌ 2 P ( g ) . The progress of product formation at two temperatures, T 1 and T 2 , is shown in the figure; where T 1 = 600 K and

Question

In a one-litre flask, 6 moles of A undergoes the reaction $A (g) ⇌ 2 P (g)$ . The progress of product formation at two temperatures, $T_{1}$ and $T_{2}$ , is shown in the figure; where $T_{1} = 600 K$ and $T_{2} = 300 K$ and take $R = 0.08 L$ bar $K^{- 1} mol^{- 1}$ .

If $(Δ G_{2}^{⊖} - Δ G_{1}^{⊖}) = R T_{2} ln x$ , then the value of x is ________

[ $Δ G_{1}^{⊖}$ and $Δ G_{2}^{⊖}$ are standard Gibb's free energy change for the reaction at temperatures T₁ and T₂, respectively]

TestHub · Accepted Answer

A ( g ) ⇌ 2 P ( g ) Conc. t = 0 6 0 At T 1 ​ 6 − 2 = 4 4 At T 2 ​ 6 − 1 = 6 2 ​ K C 1 ​ ​ = 4 ( 4 ) 2 ​ = 4 K C 2 ​ ​ = 5 ( 2 ) 2 ​ = 5 4 ​ K P 1 ​ ​ = K C 1 ​ ​ ( RT ) 1 = 4 × ( 0.08 × 600 ) = 192 K P 2 ​ ​ = K C 2 ​ ​ ( RT ) 1 = 5 4 ​ × 0.08 × 300 = 19.2 Δ G 2 ∘ ​ − Δ G 1 ∘ ​ = R T 2 ​ ln x ​ or, − R T 2 ​ ln K P 2 ​ ​ + R T 1 ​ ln K P 1 ​ ​ = R T 2 ​ ln x or, − 399 ln 19.2 + 699 ln 192 = 399 ln x or, − ln 19.2 + 2 ln 192 = ln x or, ln 19.2 ( 192 ) 2 ​ = ln x or, x = 19.2 192 × 192 ​ = 1920

Chemistry - Thermodynamics - II Question with Solution | TestHub

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