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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyHard2 minPYQ_2025

ChemistryHardmatching list

Match List - I with List - II.
Choose the correct answer from the options given below :

Options:

Answer:

Solution:

$∵ dH = dq (at P = constant) dH = CpdT^{dT} (\frac{dH}{dT})_{P} = C_{P} dU = dq (at V = constant) dU = C_{V} dT (\frac{dU}{dT})_{V} = C_{V} ∵ dG = VdP - SdT at P = constant, dP = 0$ $(\frac{d G}{d T})_{P} = - S$ at $T =$ constant $(\frac{dG}{dP})_{T} = V$

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy

⏱ 2mℹ️ Source: PYQ_2025

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