Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
ChemistryMediummultiple choice

For the cyclic process given below, which of the following relations are correct?

figure

Options:(select one or more)

Answer:
A, D
Solution:

The system goes 1 to 2 reversibly and returns 2 to 1 irreversibly. (a) Entropy change along the reversible path is ∫ δ qrev/T: true. (b) For the irreversible path the Clausius inequality gives S1 - S2 > ∫21 δ qirr/T, not equality: false. (c) ∮ δ q/T < 0 for an irreversible cycle, so the sum is not zero: false. (d) Δ Scycle = 0 for the state function, and ∮ δ q/T < 0: true. Ans: (a), (d).

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...