Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediumsingle choice
A heat engine absorbs 40 kJ of heat at 500 K and performs 10 kJ of work rejecting the remaining amount to the sink at 300 K. The entropy change for the universe is
Options:
Answer:
C
Solution:
Heat rejected = 40 - 10 = 30 kJ. The engine returns to its initial state each cycle, so only the reservoirs change. Δ Ssource = -40000/500 = -80 J/K. Δ Ssink = +30000/300 = +100 J/K. Δ Suniverse = -80 + 100 = +20 J/K. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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