Which is correct statement about ideal gas ?

Question

TestHub · Accepted Answer

Question Explanation: Analyzing entropy changes for various processes in an ideal gas.

Concept: Thermodynamics and Entropy Change.

Solution:

1: Correct. For a reversible adiabatic process, $d q = 0$ . So, entropy remains constant (isentropic), meaning $Δ S_{sys} = 0$ . Since it is reversible, $Δ S_{t o t a l} = 0$ , leading to $Δ S_{s u rr} = 0$ . Thus, $Δ S_{s u rr} = Δ S_{sys t e m} = 0$ .

2: Incorrect. For reversible isothermal expansion, $Δ S_{t o t a l} = 0$ ,so $Δ S_{sys} = - Δ S_{s u rr}$ .

3: Incorrect. In isothermal free expansion, $w = 0$ , $q = 0$ , so $Δ S_{s u rr} = 0$ .

4:Incorrect. In an irreversible process $Δ S_{sys t e m} > 0, Δ S_{s u rro u n d in g} = 0, Δ S_{t o t a l} > 0$

Chemistry - Thermodynamics - II Question with Solution | TestHub

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