Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICalculation of DSMedium2 minQB
ChemistryMediumsingle choice
The expansion process of 2.0 moles of argon proceeds so that the gas pressure increases in direct proportion to its volume. The entropy change of the gas in this process if its volume increases 2.0 times, is
Options:
Answer:
A
Solution:
P ∝ V means T = PV/nR ∝ V², so doubling V gives T₂/T₁ = 4. For argon Cᵥ,ₘ = 3R/2. ΔS = nCᵥ,ₘ ln(T₂/T₁) + nR ln(V₂/V₁) = 2 × (3R/2) ln 4 + 2R ln 2 = 2R(3 ln 2 + ln 2) = 8R ln 2 = 8 × 2 × 0.7 = +11.2 cal/K. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Calculation of DS
⏱ 2mℹ️ Source: QB
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