Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIAdiabatic Process/PolytropicMedium2 minPYQ_2020

ChemistryMediumsingle choice

What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, $R = 2 cal K^{- 1} m o l^{- 1}$ and $\log 2 = 0.301 .$

Options:

Answer:

Solution:

$n = 1, V_{i} = 3 L, V_{f} = 6 L$

$Δ S = 2.303 n R \log_{10} \frac{V_{f}}{V_{i}}$

$Δ S = 2.303 \times 1 \times 2 \log \frac{6}{3} = 2.303 \times 2 \times 0.3010$

$= 1.386 cal K^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Thermodynamics - IISubtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: PYQ_2020

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