Chemistry - Thermodynamics - II Question with Solution | TestHub

$\Delta \text{G}=\Delta {\text{G}}^{\circ }+2.303\text{ RT}\text{ log}\text{ Q}$
$=26.81\text{ kJ}+2.303\times 8.314\times 298\text{ log}\frac{2\times 10^{-3}\times 2\times 10^{-3}}{5\times 10^{-2}}$
$=26.81\left(\text{kJ}\right)+5706\left(\text{J}\right)\text{ log }\frac{4}{5}\times 10^{-4}$
$=26.81+5.706\left[-4+0.60-0.7\right]$
$=26.81+5.706\left[-4.1\right]$
$=26.81-23.37$
$=3.44{\text{ kJ mol}}^{-1}$