Heat liberated by a given amount of an ideal gas undergoing reversible isothermal process is 1200 cal at 300 K. What is the Gibbs free energy change of the gas in this process?

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Isothermal ideal gas: ΔH = 0 and ΔS = q r ev/T = −1200/300 = −4 cal/K (heat liberated). ΔG = ΔH − TΔS = 0 − 300 × (−4) = +1200 cal. Matches (b).

Chemistry - Thermodynamics - II Question with Solution | TestHub

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