Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
ChemistryMediumsingle choice
The efficiency of a Carnot cycle is 1/6. On decreasing the temperature of the sink by 65°C, the efficiency increases to 1/3. The temperature of source is
Options:
Answer:
A
Solution:
η = 1 - Tc/Th, so Tc/Th = 5/6. After lowering: (Tc - 65)/Th = 2/3. Subtract: 65/Th = 5/6 - 2/3 = 1/6, so Th = 390 K = 117°C. Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
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