Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIGibb's Free EnergyMedium2 minQB

ChemistryMediummultiple choice

For one mole of an ideal gas, select the correct statement(s):

Answer:

A, B, C

Solution:

$d G = V d P - S d T$ .

At constant $T$ : $(\frac{\partial G}{\partial P})_{T} = V > 0$ , so $G$ increases with $P$ : (A) true.

At constant $P$ : $(\frac{\partial G}{\partial T})_{P} = - S < 0$ , so $G$ decreases with $T$ : (B) true, (D) false.

At constant $T$ for an ideal gas, $Δ G = RT ln \frac{P _{2}}{P _{1}} = RT ln 10$ : (C) true.

Answer: A, B, C.

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Gibb's Free Energy

⏱ 2mℹ️ Source: QB

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