2 Zn + O 2 ⟶ 2 ZnO ; Δ G ∘ = − 616 J ( i ) 2 Zn + 2 S ⟶ 2 ZnS ; Δ G ∘ = − 293 J ( ii ) 2 S + 2 O 2 ⟶ 2 SO 2 ( g ) ; Δ G ∘ = − 408 J ( iii ) Δ G ∘ for the following reaction 2 ZnS + 3 O 2 ⟶ 2 Z

Question

2 Zn + O 2 ​ ⟶ 2 ZnO ; Δ G ∘ = − 616 J ( i ) 2 Zn + 2 S ⟶ 2 ZnS ; Δ G ∘ = − 293 J ( ii ) 2 S + 2 O 2 ​ ⟶ 2 SO 2 ​ ( g ) ; Δ G ∘ = − 408 J ( iii ) Δ G ∘ for the following reaction 2 ZnS + 3 O 2 ​ ⟶ 2 ZnO + 2 SO 2 ​ would be:

TestHub · Accepted Answer

Δ G ∘ = Δ G Z n O ∘ ​ + 2Δ G S O 2 ​ ∘ ​ − 2Δ G Z n S ∘ ​ Δ G ∘ = [ − 616 − 408 ] − [ − 293 ] = − 731 J

Chemistry - Thermodynamics - II Question with Solution | TestHub

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