Standard entropies of X 2 , Y 2 and XY 5 are 70,50 and 110 J K − 1 mol − 1 respectively. The temperature in Kelvin at which the reaction 2 1 X 2 + 2 5 Y 2 ⇌ XY 5 Δ H Θ = − 35 kJ mol −

Question

Standard entropies of X 2 ​ , Y 2 ​ and XY 5 ​ are 70,50 and 110 J K − 1 mol − 1 respectively. The temperature in Kelvin at which the reaction 2 1 ​ X 2 ​ + 2 5 ​ Y 2 ​ ⇌ XY 5 ​ Δ H Θ = − 35 kJ mol − 1 will be at equilibrium is_______. (Nearest integer)

TestHub · Accepted Answer

​ 2 1 ​ X 2 ​ + 2 5 ​ Y 2 ​ ⇌ XY 5 ​ Δ S Rxn 0 ​ = 110 − [ ( 2 1 ​ × 70 ) + ( 2 5 ​ × 50 ) ] = 110 − 160 = − 50 JK − 1 mol − 1 Δ G 0 = 0 at eqb Δ G 0 = Δ H 0 − T Δ S 0 0 = − 35000 − T ( − 50 ) T = 700 Kelvin ​

Chemistry - Thermodynamics - II Question with Solution | TestHub

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