Chemistry - Thermodynamics - II Question with Solution | TestHub
ChemistryThermodynamics - IICarnot Cycle/Cyclic processMedium2 minQB
ChemistryMediumsingle choice
Two moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in the figure. What is the ratio of temperature at B and A?
Options:
Answer:
C
Solution:
Take equal scales on both axes, so the marked angles give the slopes. A is (Vo, Po), C is (6Vo, Po), base AC = 5Vo. Let B be at height h above AC. Horizontal distance from A: h/tan 60° = h/√(3); from C: h/tan 30° = h√(3). Sum: h4/(√(3)) = 5Vo, so h/√(3) = 5/4Vo. So VB = Vo + 5/4Vo = 9/4Vo, and PB = 3Po. TB/TA = (3Po · 9Vo/4)/(Po Vo) = 27/4. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Carnot Cycle/Cyclic process
⏱ 2mℹ️ Source: QB
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