Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIMiscellaneous/MixedMedium2 minQB

ChemistryMediumsingle choice

What is the change in internal energy when a gas contracts from 377 mL to 177 mL under a constant pressure of 1520 torr, while at the same time being cooled by removing 124 J heat?

Options:

Answer:

Solution:

$Δ H = Δ U + P \cdot Δ V$

$- 124 = Δ U + \frac{1520}{760} \times (177 - 377) \times 1 0^{- 3} \times 101.3$

$Δ U = - 83.48 J$

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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