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Chemistry - Thermodynamics - II Question with Solution | TestHub

ChemistryThermodynamics - IIFree Energy and EquilibriumEasy2 minPYQ_2024
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For a certain reaction at 300 K, K=10, then ΔG° for the same reaction is – ________ ×10-1 kJ mol-1.  (Given R=8.314JK-1 mol-1)

Answer:
57
Solution:

The standard Gibbs free energy of the formation of a compound is basically the change of Gibbs free energy that is followed by the formation of one  mole of that substance from its component element available at their standard states or the most stable form of the element which is at 25 °C and 100 kPa. Its symbol is ΔfG˚.

ΔG°=-RTℓnK

=-8.314×300ln(10)

=5744.14 J/mole

=57.44×10-1 kJ/mole

Stream:JEESubject:ChemistryTopic:Thermodynamics - IISubtopic:Free Energy and Equilibrium
2mℹ️ Source: PYQ_2024

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