Standard entropy of X 2 , Y 2 and X Y 3 are 60,40 and 50 JK − 1 mol − 1 , respectively. For the reaction, 2 1 X 2 + 2 3 Y 2 → X Y 3 , Δ H = − 30 kJ , to be at equilibrium, the temperat

Question

Standard entropy of X 2 ​ , Y 2 ​ and X Y 3 ​ are 60,40 and 50 JK − 1 mol − 1 , respectively. For the reaction, 2 1 ​ X 2 ​ + 2 3 ​ Y 2 ​ → X Y 3 ​ , Δ H = − 30 kJ , to be at equilibrium, the temperature will be

TestHub · Accepted Answer

​ 2 1 ​ X 2 ​ + 2 3 ​ Y 2 ​ ⟶ X Y 3 ​ Δ S reaction ​ = 50 − ( 2 3 ​ × 40 + 2 1 ​ × 60 ) = − 40 Jmol − 1 Δ G = Δ H − T Δ S at equilibrium Δ G = 0 ​ ​ Δ H = T Δ S 30 × 1 0 3 = T × 40 ⇒ T = 750 K ​

Chemistry - Thermodynamics - II Question with Solution | TestHub

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