At a certain temperature, T (K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then, change in internal energy of the system is :NEET 2026 (Cancelled)

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According to the first law of thermodynamics:

$Δ U = q + W$

Heat absorbed by the system, $q = + 500$ J

Work done by the system, $W = - 200$ J

Substituting the given values:

$Δ U = 500 + (- 200) = 300$ J

Answer: $300$ J

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