A thermodynamic process is shown in the following figure. The pressure and volumes corresponding to some points in the figure are: P A = 3 × 10 4 Pa, P B = 8 × 10 4 Pa, V A = 2 × 10 -3 m 3 , V D = 5 ×

Question

A thermodynamic process is shown in the following figure. The pressure and volumes corresponding to some points in the figure are: P_A = 3 × 10⁴ Pa, P_B = 8 × 10⁴ Pa, V_A = 2 × 10^-3 m³, V_D = 5 × 10^-3 m³. In the process AB, 600 J of heat is added to the system and in BC, 200 J of heat is added to the system. The change in internal energy of the system in the process AC would be

TestHub · Accepted Answer

AB is at constant volume, so W AB = 0 and Δ U AB = 600 J. BC is at constant pressure P B with Δ V = V D - V A = 3 × 10 -3 m 3 : W BC = 8 × 10 4 × 3 × 10 -3 = 240 J, so Δ U BC = 200 - 240 = -40 J. U is a state function: Δ U AC = 600 - 40 = 560 J. Matches (a).

Chemistry - Thermodynamics - I Question with Solution | TestHub

Options:

Doubts & Discussion