For an ideal gas, consider only P – V work in going from an initial state X to the final state Z. The final state Z can be reached by either of the two paths shown in the figure. Which of the followin

Question

For an ideal gas, consider only P – V work in going from an initial state X to the final state Z. The final state Z can be reached by either of the two paths shown in the figure. Which of the following set choice is correct? (take $Δ S$ as change in entropy and W as work done)
N9.3.PNG
$(1) {W_{x}}_{\to y \to z} = {W_{x}}_{\to y}$
$(2) Δ {S_{x}}_{\to y \to z} = Δ {S_{x}}_{\to y}$
$(3) Δ {S_{x}}_{\to z} = Δ S_{x \to y} + Δ S_{y \to z}$
$(4) W_{x \to z} = W_{x \to y} + W_{y \to z}$

Options:

Answer:

B

Solution:

Since entropy is a state function
$Δ S_{X \to Z} = Δ S_{X \to Y} + Δ S_{Y \to Z}$
Now $W_{Y \to Z} = 0$ (for isochoric)
$W_{X \to Y \to Z} = W_{X \to Y}$

TestHub · Accepted Answer

Since entropy is a state function Δ S X → Z = Δ S X → Y + Δ S Y → Z Now W Y → Z = 0 (for isochoric) W X → Y → Z = W X → Y

Chemistry - Thermodynamics - I Question with Solution | TestHub

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