1 m 3 of neon gas initially at 273.2 K and 10 atm undergoes expansion isothermally and reversibly to final pressure of 1 atm . The work done by the gas is

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TestHub · Accepted Answer

Work done in an isothermal reversible process is given by:

$W = - n R T \ln \frac{V_{2}}{V_{1}} = - n R T \ln \frac{P_{1}}{P_{2}}$

To apply the above equation, first, we calculate $n$ using $P V = n RT$ .

So,

$W = - \frac{1 0 ^{4}}{0.0821} \times 8.314 \times 2.303 lo g \frac{10}{1}$

$W = - 2332 k J$

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