Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IAdiabatic Process/PolytropicEasy2 minQB
ChemistryEasysingle choice
A real gas is taken adiabatically from (1 bar, 50 L, 300 K) to (2 bar, 30 L, 300 K) against a constant external pressure of 2 bar. The enthalpy change for the process is
Options:
Answer:
D
Solution:
q = 0, so Δ U = w = -PextΔ V = -2 × (30 - 50) = +40 bar-L = 4000 J. Δ(PV) = 2 × 30 - 1 × 50 = 10 bar-L = 1000 J. Δ H = 4000 + 1000 = 5000 J. Matches (d).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB
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