An ideal gaseous sample at initial state (P 0 , V 0 , T 0 ) is allowed to expand to volume 4V 0 using three different processes. Process 1: PV 2 = K 1 . Process 2: PV = K 2 . Process 3: P = K 3 (constant). If W 1 , W 2 and W 3 are the magnitudes of work done by the gas in the three processes, then

W 1 = P 0 V 0 2 (1/(V 0 ) - 1/(4V 0 )) = 0.75 P 0 V 0 . W 2 = P 0 V 0 ln 4 = 1.386 P 0 V 0 . W 3 = P 0 (4V 0 - V 0 ) = 3 P 0 V 0 . So W 3 > W 2 > W 1 , which is (d).

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ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricMedium2 minQB

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An ideal gaseous sample at initial state (P₀, V₀, T₀) is allowed to expand to volume 4V₀ using three different processes. Process 1: PV² = K₁. Process 2: PV = K₂. Process 3: P = K₃ (constant). If W₁, W₂ and W₃ are the magnitudes of work done by the gas in the three processes, then

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Solution:

W₁ = P₀V₀²(1/(V₀) - 1/(4V₀)) = 0.75 P₀V₀. W₂ = P₀V₀ln 4 = 1.386 P₀V₀. W₃ = P₀(4V₀ - V₀) = 3 P₀V₀. So W₃ > W₂ > W₁, which is (d).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric

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