Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minPYQ_2019

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Consider the reversible isothermal expansion of an ideal gas in a closed system at two different temperatures $T_{1}$ and $T_{2} (T_{1} < T_{2})$ . The correct graphical depiction of the dependence of work done $(w)$ vs the final volume $(V)$ is:

Options:

Answer:

Solution:

$w = - nRTln (\frac{v_{2}}{v_{1}})$

$w = - nRTln (\frac{v_{f}}{v_{i}})$

$|w| = nRTln \frac{v_{b}}{v_{i}}$

$|w| = nRT (\ln v_{f} - \ln v_{i})$

$|w| = nRTln v_{f} - nRTln v_{i}$

$y = mx - c$

So for $(T_{2} > T_{1})$ Intercept of $T_{2}$ would be more negative than $T_{1}$ and slope of curve $T_{2}$ would be more than slope of curve $(T_{1})$ .

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2019

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