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ChemistryThermodynamics - IAdiabatic Process/PolytropicMedium2 minQB

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A liquid confined inside an adiabatic container is suddenly taken from state 1 to state 2 by a single stage process as shown, then $Δ H$ is

Options:

Answer:

Solution:

$Q = 0$

$Δ U w Δ H = Q + w = w = - P_{0} (4 V_{0} - V_{0}) = - 3 P_{0} V_{0} = Δ U + (P_{2} V_{2} - P_{1} V_{1}) = - 3 P_{0} V_{0} + (4 P_{0} V_{0} - 2 P_{0} V_{0}) = - 3 P_{0} V_{0} + 2 P_{0} V_{0} = - P_{0} V_{0}$

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: QB

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