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ChemistryThermodynamics - IAdiabatic Process/PolytropicHard2 minQB
ChemistryHardsingle choice

An ideal gas (γ = 1.4), originally at 300 K and 100 kPa, is compressed adiabatically in a single step against a constant external pressure until its temperature reaches 600 K. What is the minimum external pressure that must be applied?

Options:

Answer:
A
Solution:

q = 0, so nCv(T2 - T1) = -Pext(V2 - V1) with Cv = 5/2R and the final pressure equal to Pext. With V2 = nRT2/Pext and V1 = nRT1/P1: 5/2(300) = (Pext)/P1(300) - 600, so (Pext)/P1 = 1350/300 = 4.5, giving 450 kPa. (A reversible adiabatic path would end at 100 × 23.5 = 1131 kPa, which is the distractor in option b.) Matches (a).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
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