Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minQB
ChemistryEasymatching list
Match Column I (Differential of U) with Column II (System)
Column I | Column II |
|---|---|
P) dU = nCV,mdT | i) Ideal gas |
Q) dU = nCV,mdT + (n2a)/(V2)dV | ii) van der Waals gas |
R) dU = (n2a)/(V2)dV | iii) van der Waals gas, isothermal process |
S) dU = 0 while dV ≠ 0 | iv) Ideal gas, isothermal process |
Options:
Answer:
B
Solution:
An ideal gas has U depending only on T (P – i). A van der Waals gas adds the attraction term n2a/V2 (Q – ii); at constant T only that term survives (R – iii). An ideal gas at constant T has dU = 0 even when V changes (S – iv).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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