One mole of an ideal monoatomic gas at 1600 K and 256 atm is expanded to a final state at 400 K and 1 atm by a reversible path: adiabatic expansion first, then isothermal expansion. The magnitude of n

Question

One mole of an ideal monoatomic gas at 1600 K and 256 atm is expanded to a final state at 400 K and 1 atm by a reversible path: adiabatic expansion first, then isothermal expansion. The magnitude of net work done by the gas (in cal, nearest integer; R = 2 cal/K-mol) is

TestHub · Accepted Answer

Adiabatic to 400 K: P' = 256 (400/1600) 5/2 = 256/32 = 8 atm. w ad = 1.5R×1200 = 3600 cal. Isothermal 8 to 1 atm: RTln8 = 800×2.0794 = 1664 cal. Total = 3600 + 1664 = 5264 cal. Ans = 5264.

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