Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IAdiabatic Process/PolytropicEasy2 minQB
ChemistryEasynumerical

One mole of an ideal gas (γ = 1.5) is expanded isothermally at 27°C until its volume triples. It is then compressed adiabatically to its original volume. The magnitude of the net work done by the gas (in J, nearest integer) is

Answer:
912.00
Solution:

w1 = RTln3 = 2494.2×1.0986 = 2740 J. CV = R/(γ-1) = 2R. T3 = 300×30.5 = 519.6 K. w2 = -CVΔ T = -2×8.314×219.6 = -3652 J. Net = 2740 - 3652 = -912 J, magnitude 912 J. Ans = 0912.

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Adiabatic Process/Polytropic
⏱ 2mℹ️ Source: QB

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